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108y^2-56y-32=0
a = 108; b = -56; c = -32;
Δ = b2-4ac
Δ = -562-4·108·(-32)
Δ = 16960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16960}=\sqrt{64*265}=\sqrt{64}*\sqrt{265}=8\sqrt{265}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-8\sqrt{265}}{2*108}=\frac{56-8\sqrt{265}}{216} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+8\sqrt{265}}{2*108}=\frac{56+8\sqrt{265}}{216} $
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